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AveGali [126]
3 years ago
11

A pizza has a diameter of 14 inches what is the approximate circumference

Mathematics
1 answer:
Savatey [412]3 years ago
7 0
To find the circumference of a circle you can use either of these equations
3.14 X Diameter or 2 X 3.14 X Radius. But in this case we will use the first one. So 3.14 X 14 = 47.6 so the circumference of this circle would be 47.6 inches.
                                                                 I hope this helps :) 
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HELP ME PLEASEEE! Ty:)
Jlenok [28]
I can help you if you mark me as braì LG
5 0
3 years ago
Math graph equation. <br> (Picture.)
vladimir1956 [14]

Answer:

y = -2x + 3 is the required equation

Step-by-step explanation:

From the graph we will get two ordered pairs

If we see that When x=0 then y=3  and when x = 1 then  y=1

Now from this we can find the slope of the Graph

So slope of graph = (y2 - y1) / (x2-x1)

                               =(1-3) / (1-0)

                                =-2

So

Slope = m = -2

Now the equation is

y = mx + b

We have to find the value of b

as we have two ordered pairs we can take any of it to find the value of b because line passes through those points

taking (0,3) as a point

y= mx + b

put values

3 = -2*(0) + b

so

b=3


Now the equation of the line in this form is

y = mx + b

which is

y = -2x + 3

5 0
3 years ago
Find the area of the circle round your answer to the nearest 10th
zhannawk [14.2K]

Answer:

The area is 19.63.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :
mel-nik [20]

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
3 years ago
3. Find the range of this function.
valkas [14]

Answer:

The answer is three

Step-by-step explanation:

7 0
3 years ago
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