In the picture we can see the graph represents of the function f(x)=x²-2x+3 that is curve graph.
Given that,
We have to find the graph represents the function f(x)=x²-2x+3.
We know that,
The quadratic function is f(x)=x²-2x+3.
This is a vertical parabola open downward
The vertex is a maximum
We know,
A vertical parabola's equation in vertex form is equal to
y= a(x-h)²+k
where
a is a coefficient
(h,k) is the vertex
Here
a=1
(h,k)=(0,3) is vertex
The y-intercept is the point (0,3) is value of y when the value of x is equal to zero (is the same point that the vertex)
The x-intercepts are the points is values of x when the value of y is equal to zero
Therefore, In the picture we can see the graph represents of the function f(x)=x²-2x+3.
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Answer:
y= -x-8
Step-by-step explanation:
The ones in the equation are in subscript, couldn't get the equation creator to work properly....DO NOT multiply by one, they are merely subscript meant to help you identify which pair to use.
y-y1=m(x-x1)
-5=x1
-3=y1
-1=m
y- -3=-1(x- -5) then you arrive at y+3=-1(x+5)
y+3=-x-5 now you isolate the y on the left y=-x-8
Answer:
Wha-?
Step-by-step explanation: