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2 years ago

1+2+3+4+5+6+7+8+9+10 Hi, Please help me... With my Bor*edom?

Mathematics

2 answers:

Angelina_Jolie [31]2 years ago

8 0

Answer:

Step-by-step explanation:

hope it helps you.....

uysha [10]2 years ago

4 0

Answer:

1+2+3+4+5+6+7+8+9+10 = 55

Answer 2: To fix boredom, go surfing, mountain biking, cook, play video games, play piano, guitar, drums, etc.

Step-by-step explanation:

hehe

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What is 0.98 as fraction

Montano1993 [528]

0.98 as a unsimplified fraction would be 98/100. The simplified fraction would be 49/50 hope this helped

6 0

3 years ago

I really need help with this ASAP

Alexandra [31]

Answer:

No. of boxes = 10

Oranges per box = 56

Total no. of oranges = 56*10=560

No. of bad oranges = 560/40= 14

(i) Probability of bad orange = 14/560 = 1/40

(ii) no of oranges expected to be bad = 14 ( found above)

Hope it helps.............. :)

7 0

3 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

4x-y=20 find the X and Y intercepts from the equation

GalinKa [24]

Answer:

its c

Step-by-step explanation:

i took it

7 0

3 years ago

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$