Answer:
70 cents each snickers bar
Step-by-step explanation:
Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB
The given expression is
![f(x) = \frac{3(x+2}{(x+2)(x+6)}](https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%5Cfrac%7B3%28x%2B2%7D%7B%28x%2B2%29%28x%2B6%29%7D%20)
And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2
And a function is undefined when denominator is zero. And at x=-6, denominator become zero.
So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .
Answer:
i cant see the attachment
Hey there, Bulgogi!
The correct answer will be the first one since [I'm assuming] you know that to calculate the percentage of something, it's the amount of that something divided by the total amount but since only 30 students voted [12+18] multiplied by 100.
So, we are calculating the percentage on votes and 12 students voted for Candidate A so our Numerator will be 12 and our Denominator will be the total amount of student who voted, so 30 [or 12+18]
Once put into a fraction, we will get
![\frac{12}{12+18}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7B12%2B18%7D%20)
which would be equals to 2/5 or 0.4. Now we multiply by 100 and we get a total of 40% for Candidate A.
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