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2 years ago

Four adult alligators weigh 1,812 kilograms. If each alligator weighs the same, how many kilograms does one alligator weigh?

1 answer:

3 0

Each alligator would weigh 453 kilograms. I got this answer by taking 1812 and dividing it by 4 to get my answer. Hope this helps! :D

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A movie theatre sold 1,000 tickets and made $7160 in one night. If an adult tickets costs 9$ and a children's costs 5$, how many

victus00 [196]

540 adult tickets were sold and 460 kid tickets were sold

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3 years ago

Describe how the graph of each function differs from the graph of f(x)=|x|. Then determine the domain and range.

Brilliant_brown [7]

A. We can compress the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $0$ Since $0$ , the graph of the function $g(x)= 0.6|x|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction.

B. We can stretch the graph of the function $f(x)=|x|$ in the y-direction by multiplying the whole function by a constant C, such that $C>1.$ Since $4>1,$ , the graph of the function $g(x)= 4|x-3|$ is obtained from the graph of the function $f(x)=|x|$ by compression in the y-direction and translation 3 units to the right.

C. We can flip the graph of the function $f(x)=|x|$ upside down by multiplying the whole function by −1, then translate 1 unit to the left and 5 units up. Then we will get the function $g(x)=-|x+1|+5.$

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2 years ago

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

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3 years ago

Mujer culona

KIM [24]

Mujer culona mujer culona mujer culona

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3 years ago

A baker uses 2.327 kilograms of blueberries for muffins. There are four packages at the fruit market. Which amount is closest to

irinina [24]

Answer:

2.33 kg

Step-by-step explanation:

If the baker needs to use 2.327 kilograms of blueberries, we are going to subtract the amount of the packages to the amount he needs and we'll see which is the smallest number.

In the case of 2.3, 2.327 - 2.3 = .027

In the case of 2.42, 2.327 - 2.42 = -0.09

In the case of 2.33, 2.327 - 2.33 = -0.003

In the case of 2.4, 2.327 - 2.4 = -0.07

Therefore, the closest amount to 2.327 is the 2.33 package.

4 0

2 years ago