The sum of the first n terms of sequence 85 +85(.9) +85(.9)² + ... would be 348.08.
<h3>What is the sum of terms of a geometric sequence?</h3>
Let's suppose its initial term is a , multiplication factor is r and let it has total n terms,
then, its sum is given as:
(sum till nth term)
Given geometric sequence;
85 +85(.9) +85(.9)² + ...
a = 85
r = 0.9
its sum is given as:
Thus,
The sum of the first n terms of sequence 85 +85(.9) +85(.9)² + ... would be 348.08.
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Answer:
16.66666666666667%
Step-by-step explanation:
Answer:
y=-7x-9
Step-by-step explanation:
y=mx+b(where m is slope and b is y intercept)
y=-7x+b
plugging the number in we get
12=-7(-3)+b
12=21+b
b=-9
so y= -7x-9
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