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vagabundo [1.1K]
3 years ago
8

Fill in the chart Tons ____ Pounds 1187 Ounces_____

Mathematics
2 answers:
babunello [35]3 years ago
3 0
Tons 0.5935 Pounds 1187 ounces 18992
Marianna [84]3 years ago
3 0

Answer:

the pounds 1187 the ounces 18992 the tons 0.5935

Step-by-step explanation:

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The volume of a cube is 27 cubic meters. what is its surface area in square meters?
erma4kov [3.2K]

To find the answer, take the measurement of an edge of the cube, multiply it by 6, and then square that number.

Ex:

Edge = 16

Faces in 1 cube = 6

     6 * 16 = 96

96^2 (which is just 96 * 96)= 9,216


I hope this helps! :)

4 0
2 years ago
Five more than three times a number is that number increased by 40. What is the number
rewona [7]
Let the number be n.

Then 3n+5 = n+40
Combining like terms, we get

         2n = 35, and so n = 35/7, or 17 1/2.

6 0
3 years ago
I need help pleaseeeee
Ira Lisetskai [31]
2.1 ÷ 1.488 = 1.41
1.41 rounded to the nearest tenth is 1.4
so your answer is 1.4
7 0
3 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
Here is a growing pattern of squares:
Flura [38]

Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

3 0
1 year ago
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