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3 years ago

Answer asap! will give brainliest! question is in pic

Mathematics

1 answer:

lana [24]3 years ago

4 0

Answer:

UW=14

Step-by-step explanation:

First we know that UV+VW=UW, so:

4+x+10=2x+14

Solve for x first:

x+10=2x+10

10=x+10

x=0

Then, substitute the X

2(0+14)=14=UW

To check your answer, substitute and add UV and VW

4+(0)+10

<em>Hope this helped! Have a good day!</em>

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What is the volume of a sphere with a radius of 4

Ede4ka [16]

Step-by-step explanation: To find the volume of a sphere, start with the formula for the volume of a sphere which is shown below.

$V = \frac{4}{3}\pi r^{3}$

Here, we are given that our sphere has a radius of 4 units.

So plugging into the formula, we have $(\frac{4}{3})(\pi)(4 units)^{3}$ .

Start by simplifying the exponent.

(4 units)³ is equal to (4 units) (4 units) (4 units) or 64 units³.

So we have $(\frac{4}{3})(\pi)(64 units^3})$ .

Next, we multiply (4/3)(64) which can

be thought of as (4/3)(64/1)

So multiplying across the numerators and across the denominators,

we have $\frac{256}{3} \pi units^{3}$ .

5 0

3 years ago

I just need examples of these things, I have to make my own problems and solve them:

poizon [28]

1) x+17=20
x-10=30

2) x/4=20
x/30=2

3) 4(x+5)=40

4) x+3.2=6

5) A pizza place sells pizza for $5 per box. If I had $20 how many pizzas can I buy in all? (5x=20)

Hope this helps! Have a wonderful day.

6 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

What is the rate of change?

slega [8]

Answer:

X= -1. Y=-5

Step-by-step explanation:

The x decreases by -1 and the y decreases by -5 .

3 0

3 years ago

a rectangle is a four sided flat shaped where every interior angles is a right angle. Therefore, opposite sides aRE PARALLEL and

Schach [20]

This is true. There is no question connected which is why there are no answers!

5 0

3 years ago