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4 years ago

6

What's. Y+1=2(x-5) in Ax+by=c form

1 answer:

Dmitry [639]4 years ago

4 0

Y + 1 = 2(x - 5)....distribute the 2 thru the parenthesis
y + 1 = 2x - 10...subtract 1 from both sides
y = 2x - 10 - 1
y = 2x - 11....subtract 2x from both sides
-2x + y = -11 ...multiply by -1 to make A positive
2x - y = 11 <===

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Answer:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is $\frac{-6-0}{6-5}$ ⇒ C

Step-by-step explanation:

The formula of the slope of a line passes through points $(x_{1},y_{1})$ and $(x_{2},y_{2})$

is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ The line passes through points (5 , 0) and (6 , -6)

∴ $x_{1}$ = 5 and $x_{2}$ = 6

∴ $y_{1}$ = 0 and $y_{2}$ = -6

Substitute these values in the formula of the slope

∵ $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∴ $m=\frac{-6-0}{6-5}$

Let us look to the answer and find the same formula

The answer is:

The correct way to set up the slope formula for the line that passes through points (5 , 0) and (6 , -6) is $\frac{-6-0}{6-5}$

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