Take the logarithm of both sides. The base of the logarithm doesn't matter.


Drop the exponents:

Expand the right side:

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :


Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

You can stop there, or continue simplifying the solution by using properties of logarithms:



You can condense the solution further using the change-of-base identity,

Consider the offered option:
if suppose, that unknown side is '?', then
2*(3x-3)+2*'?'=10x+6;
6x-6+2*'?'=10x+6;
2*'?'=4x+12;
'?'=2x+6
Answer: 2x+6
Answer:
Step-by-step explanation:
In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:
and
3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and
So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):
* and
and
so
** and, in standard form:
4y = -3x + 29 and
3x + 4y = 29***
* : point-slope form
** : slope-intercept form
*** : standard form
Answer:
First, write out the prime factorization of both 12 and 80: 12 = 2 x 2 x 3 and 80 = 2 x 2 x 2 x 2 x 5. Now collect only the prime numbers that each of them share in their factorizations, which are only two 2's. Thus, the greatest common factor between 12 and 80 is 2 x 2 = 4. Step-by-step explanation:
Answer:
(-4,-3)
Step-by-step explanation:
Find the point where the 2 lines intersect. In this problem it is (-4,-3)
x=-4
y=-3