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3 years ago

10

Let’s work with some actual data this time. Go online to research and find a set of real-world data in two variables. The data c

an be in tabular form or in a scatter plot. Choose data that has a reasonable number of data points so you’re able to uncover trends. For the purposes of this activity, the data must not show a linear association. Describe the data you’ve identified in a sentence or two, and include a link to the data.

2 answers:

HACTEHA [7]3 years ago

6 0

Answer:

First u have to add the var

Step-by-step explanation:

4vir4ik [10]3 years ago

6 0

Answer:

well you gotta dp this yourself but ijust made up data between nike and jordans

Step-by-step explanation:

You might be interested in

A desk is on sale for $380 which is 20% of the original price. Which equation can be used to determine the amount of money saved

elena-s [515]

Answer:

S = 380 - 380*80%

Step-by-step explanation:

Given:

The original price of the desk: $380
Discount: 20%

So, the new price of the desk after discounting is:

380(100% - 20%)

= 380*80%

= 304$

The amount of money saved: 380 - 304 = 76$

Hence, the equation can be used to determine the amount of money saved is:

Saving = 380 - 380*80%

Hope it will find you well.

8 0

3 years ago

Read 2 more answers

Which expression haves the same value as 59.2- 84.7

Radda [10]

- 84.7 + 59.2, this is your expression

3 0

3 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

amm1812

Answer:

Given:

Sham: n= 20, x=0.44, s=1.24,

Magnet:n= 20, x =0.49, s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

$\frac{s1^2}{s2^2}$

$\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037$

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom $= n - 1 = 20 - 1 = 19$

Magnet: degrees of freedom $= n - 1 = 20 - 1 = 19$

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

$f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]$

$f[0.025, 19, 19], f[0.975, 19, 19]$

$(2.526, 0.3958)$

The rejection region:

Reject H0, if F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0

3 years ago

Translate and solve: What number is 283% of 1.89? Do not round.

zaharov [31]

I believe it should be 5.3487 since 283% is converted into 2.83 and multiplied by 1.89.

7 0

3 years ago