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Lyrx [107]
3 years ago
12

Write each mixed numbers or decimal as a percent.

Mathematics
1 answer:
TEA [102]3 years ago
4 0
The answer would be 180%
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Which of the following best describes how the y values are changing over each interval? x y 1 20 2 40 3 80 4 160 5 320 They are
MAVERICK [17]
<h3>Answer</h3>

They are being multiplied by 2 each time.

4 0
3 years ago
Read 2 more answers
For questions 2 and 3 plot the points in the coordinate plane. Then determine whether AB and CD are congruent. Explain your answ
max2010maxim [7]

Answer:

  2. congruent

  3. congruent

Step-by-step explanation:

Segments will be congruent if their lengths are the same. Their lengths will be the same if the sum of squares of the x- and y-differences of their endpoint coordinates are the same.

2. B-A = (-4-(-4), 8-1) = (0, 7)

  D-C = (5-(-2), -5-(-5)) = (7, 0)

The total of 0² and 7² is the same as the total of 7² and 0², so these segments are congruent. (They are both of length 7.)

__

3. B-A = (2-4, 6-1) = (-2, 5)

  D-C = (-4-(-2), -3-2) = (-2, -5)

The sum of (-2)² and 5² is the same as the sum of (-2)² and (-5)², so these segments are congruent. (They both are of length √29.)

6 0
4 years ago
You roll a 6 sided dice what is the probability of rolling a number greater than two and then rolling a number less than three
Alexandra [31]

First answer is 4 chances and second answer is 2 chances

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B6%7D%20" id="TexFormula1" title=" \fra
timurjin [86]

\bf \cfrac{4}{3}=\cfrac{x}{6}\implies \stackrel{\textit{cross-multiplying}}{(6)4=(3)x}\implies 24=3x\implies \cfrac{24}{3}=x\implies 8=x

5 0
4 years ago
. A regular hexagon is composed of 12 congruent 30 o -60 o -90 o triangles. If the length of the hypotenuse of one of those tria
sergey [27]

see  the attached figure to better understand the problem

Let

2L---------> lenght side of hexagon


we know that

in one of those triangles

sin 30=1/2

sin 30=L/hypotenuse

solve for L

L=hypotenuse*sin 30-------->L=( 1 8 √ 3 )*(1 /2)------> L=9√3 units


Find the perimeter

perimeter=(2L)*6--------> L*12-------> Perimeter=9√3*12--------->108√3 units


therefore


the answer is

the perimeter of the regular hexagon is 108√3 units

5 0
4 years ago
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