Question

Write an equation of the line, in slope-intercept form, that passes through (-2, 5) and (1, -1).

Answer 1

Answer:

y = -2x + 1

Step-by-step explanation:

Formulae:

Slope: $m=\frac{y_2-y_1}{x_2-x_1}$

• m = slope
• y₂ = second y-value
• y₁ = first y-value
• x₂ = second x-value
• x₁ = first x-value

Point-slope form: $y-y_1=m(x-x_1)$

• y₁ = first y-value
• m = slope
• x₁ = first x-value

Slope-intercept form: $y=mx+b$

• m = slope
• b = y-intercept value

Calculations:

$m=\frac{-1-5}{1-(-2)}\\m=\frac{-6}{3}\\m=-2$

$y-5=-2(x-(-2))\\y-5=-2(x+2)\\y-5=-2x-4\\y=-2x+1$