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Lapatulllka [165]
3 years ago
8

Need done ASAP please and thank you

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0

Answer:

12

Step-by-step explanation:

5x + x + 18 = 90

collect like terms:

5x + x = 6x ( when an x alone imagine a 1 infront of it)

solve:

6x + 18 = 90

90 - 18 = 72

6x = 72

72 ÷ 6 = 12

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Answer: # 15 is x=-12 and #16 is x=24

Step-by-step explanation:

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you pay $14.82 for 1.5 pound of ham. you buy 2.25 pounds of roast beef for $12.40 per pound. How much less does ham cost per pou
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4 years ago
13
zepelin [54]

Answer:

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

Step-by-step explanation:

We need to find equation from the table given

x     f(x)

3     -5

7     -2

11     1

15    4

We can write equation in the form of y=mx+b

where m is slope and b is y-intercept.

Finding Slope

We can used the slope formula to find slope: Slope=\frac{y_2-y_1}{x_2-x_1}

From the table we have: x_1=3, y_1=-5, x_2=7, y_2=-2

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{7-3} \\Slope=\frac{-2+5}{7-3}\\Slope=\frac{3}{4}

So, we get slope m=\frac{3}{4}

Now, finding y-intercept

Using the slope m=\frac{3}{4} and point (3,-5) we can find y-intercept

y=mx+b\\-5=\frac{3}{4}(3)+b\\-5=\frac{9}{4}+b\\b=-5-\frac{9}{4}\\b=\frac{-5*4-9}{4}\\b=\frac{-20-9}{4}\\b=\frac{-29}{4}

The y-intercept is b=\frac{-29}{4}

So, the equation having slope m=\frac{3}{4} and y-intercept b=\frac{-29}{4} will be:

y=mx+b\\y=\frac{3}{4}x-\frac{29}{4}

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

6 0
3 years ago
the length of a rectangle is 9 inches more than the width. the perimeter is 54 inches. Find the length and width of the rectangl
Keith_Richards [23]
W is width W+9 is length W+W+9=54 2w=45 45/2 W=22.5 Width is 22.5 length is 31.5
7 0
3 years ago
Simplify the expression
kow [346]

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

4 0
3 years ago
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