Answer:
(1) 2π - x² = 0 (2) x = 2.5 cm (3) perimeter = 10 cm
Step-by-step explanation:
(1)The area of the circular coin without the inner square removed is πr² where r = 3 cm is the radius of the coin. So, the area of the coin without the inner square removed is πr² = π(3 cm)² = 9π cm²
The area of the square of x sides removed from its center is x².
The area A of the each face of the coin is thus A = 9π - x²
Since the area of each face of the coin A = 7π cm²,
then
7π = 9π - x²
9π - 7π - x² = 0
2π - x² = 0
(2) Solve the equation 2π - x² = 0
2π - x² = 0
x² = 2π
x = ±√(2π)
x = ± 2.51 cm
Since x cannot be negative, we take the positive answer.
So, x = 2.51 cm
≅ 2.5 cm
(3) Find the perimeter of the square
The perimeter of the square, p is given by p = 4x
p = 4 × 2.51 cm
= 10.04 cm
≅ 10 cm
90 square inches i think!!!
The answer is the
The shape has 6 equal Square face
Because each side had 6
That on of the answer the next the shape has 6 vertices
Also the shape is soild
Step-by-step explanation:
2 + 3 × (8 + 53 ÷ 1)
we first work out the equation in the brackets
so...
(8 + 53 ÷ 1)
division comes first so we divide 53÷1 which is 1 so the equation looks like this:
(8+53)
we work this out and get
61
then we work the rest out
2 + 3 × <u>61</u>
multiplication comes first so...
3×61= 183
and
2+ 183= 185
Therefore 2 + 3 × (8 + 53 ÷ 1)= <u>185</u>
Hope this helped- have a good day bro cya)
Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you! mark me as brainliest pls
§ALEX§