Answer:
El espesor de un chip es de 0.12mm
Y el diámetro de un átomo de cobre, mide aprox:
0.00000000133 m
Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm
Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm
Primero, escribamos ambos valores en las mismas unidades, sabiendo que:
1m = 1000mm
Podemos reescribir:
0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm
Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm
Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:
N = (0.12mm)/(0.00000133mm) = 90,225.6
Redondeamos al próximo número entero:
N = 90,226
Esa es la cantidad de átomos que se necesitan.
Answer:
The correct option is;
A. A number line that goes from 95 to 103. A closed circle is at 98.6. Everything to the right is shaded.
Step-by-step explanation:
To represent x greater-than-or-equal-to 98.6 on the number line we note that an open circle stands for either a less than or a greater than, while an open circle stands for either less than or equal to or greater than or equal to
The correct way to represent x greater than or equal to 98.6 on the number line, we indicate the point 98.6 with a closed circle and we shade everything in the region of the solution which is to the right of the closed circle
Therefore the correct option is A. A number line that goes from 95 to 103. A closed circle at is at 98.6. Everyting to the right is shaded.
If you multiply a positive by a negative it’s negative same goes for dividing if it’s two negatives then the answer is positive hope this helped
