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Anon25 [30]
3 years ago
11

What is the answer for 4/6 - 2/9?

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0

Answer: The answer is 0.4

Step-by-step explanation:

Since you're subtracting <em>fractions</em>, we will get a decimal. Fractions are not whole numbers.

Len [333]3 years ago
4 0

Answer:

4/9

Step-by-step explanation:

I think

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Anastasy [175]

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4 0
3 years ago
5x+9=2x+7+3x-15
andrew11 [14]

Answer:

No Solutions

Step-by-step explanation:

Step 1:

5x + 9 = 2x + 7 + 3x - 15  Equation

Step 2:

5x + 9 = 5x - 8   Add and Subtract

Step 3:

9 = - 8    Subtract 5x on both sides

Answer:

9 ≠ - 8       9 cannot equal - 8

Hope This Helps :)

3 0
4 years ago
Read 2 more answers
Suppose that 20% of the residents in a certain state support an increase in the property tax. An opinion poll will randomly samp
aleksklad [387]

Answer:

95.44% probability the resulting sample proportion is within .04 of the true proportion.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sampling distribution of the sample proportion in sample of size n, the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.2, n = 400

So

\mu = 0.2, s = \sqrt{\frac{0.2*0.8}{400}} = 0.02

How likely is the resulting sample proportion to be within .04 of the true proportion (i.e., between .16 and .24)?

This is the pvalue of Z when X = 0.24 subtracted by the pvalue of Z when X = 0.16.

X = 0.24

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.24 - 0.2}{0.02}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 0.16

Z = \frac{X - \mu}{s}

Z = \frac{0.16 - 0.2}{0.02}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

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6 0
3 years ago
Read 2 more answers
Help or don’t if so thank you
NikAS [45]

Answer: 12.60 per CD

Step-by-step explanation:

Tax 0.80 * 3 = 2.40

40.20 - 2.40 = 37.80

37.8 / 3 = 12.60

5 0
3 years ago
A jet travels 4680 miles against the wind in eight hours and 5720 miles in the wind in the same amount of time what is the rate
Kryger [21]

9514 1404 393

Answer:

  • jet: 650 mph
  • wind: 65 mph

Step-by-step explanation:

The speed against the wind is ...

  4680 mi/(8 h) = 585 mi/h

The speed with the wind is ...

  5720 mi/(8 h) = 715 mi/h

The speed of the airplane in still air is the average of these speeds:

  (585 +715)/2 = 650 mi/h . . . speed in still air

The speed of the wind is the difference between the airplane speed and the speed in the wind:

  715 -650 = 65 mi/h . . . speed of the wind

_____

<em>Additional comment</em>

If p and 'a' represent the speeds of the plane and the air, the speeds with and against the wind are ...

  p + a = with

  p - a = against

If we average these, we get ...

  ((p +a) +(p -a))/2 = (with + against)/2

  p = (with + against)/2 . . . . . . . the formula we used above

8 0
3 years ago
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