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Sonbull [250]
3 years ago
6

Please help me its worth a lot of points!!!!

Mathematics
2 answers:
GarryVolchara [31]3 years ago
7 0

Answer:

A,C,E

Step-by-step explanation:

The vertices of the triangle are X , M , and A , so the names can be any order of X, M and A.

Aleksandr-060686 [28]3 years ago
5 0

Answer:

A, C, E

Step-by-step explanation:

Those are the points of the triangle on the ends so you can use AXM, MAX, and XMA as names because you can go in any order of points you want to

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Classify the polynomial according to its degree and number of terms 3x^2+8x​
Sunny_sXe [5.5K]

Answer:

Classifying Polynomials

Polynomials can be classified two different ways - by the number of terms and by their degree.

1. Number of terms.

A monomial has just one term. For example, 4x2 .Remember that a term contains both the variable(s) and its coefficient (the number in front of it.) So the is just one term.

A binomial has two terms. For example: 5x2 -4x

A trinomial has three terms. For example: 3y2+5y-2

Any polynomial with four or more terms is just called a polynomial. For example: 2y5+ 7y3- 5y2+9y-2

Practice classifying these polynomials by the number of terms:

1. 5y

2. 3x2-3x+1

3. 5y-10

4. 8xy

5. 3x4+x2-5x+9

Answers: 1) Monomial 2) Trinomial 3) Binomial 4) Monomial 5) Polynomial

2. Degree. The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s).

Examples:

5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

3x4+4x2The highest exponent is the 4 so this is a 4th degree binomial.

8x-1 While it appears there is no exponent, the x has an understood exponent of 1; therefore, this is a 1st degree binomial.

5 There is no variable at all. Therefore, this is a 0 degree monomial. It is 0 degree because x0=1. So technically, 5 could be written as 5x0.

3x2y5 Since both variables are part of the same term, we must add their exponents together to determine the degree. 2+5=7 so this is a 7th degree monomial.

Classify these polynomials by their degree.

1.7x3+52+1

2.6y5+9y2-3y+8

3.8x-4

4.9x2y+3

5.12x2

Answers 1) 3rd degree 2) 5th degree 3) 1st degree 4) 3rd degree 5) 2nd degree

6 0
3 years ago
Given g(x)=5x+2 what is the value of g(3)
Paraphin [41]

Answer:

g(3) = 17

Step-by-step explanation:

Step 1: Define

g(x) = 5x + 2

g(3) = x = 3

Step 2: Substitute and Evaluate

g(3) = 5(3) + 2

g(3) = 15 + 2

g(3) = 17

7 0
3 years ago
Read 2 more answers
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
3 years ago
Point K is rotated 90". The coordinate of the pre-image point K was (2,6) and its image K' is at the coordinate (-6, -2) Find th
tensa zangetsu [6.8K]

Answer:

Clockwise

Step-by-step explanation:

Sorry I answered late

3 0
2 years ago
Read 2 more answers
The school play earned $11,271 in ticket sales. If the cost of each ticket was $13, how many tickets were sold?
mojhsa [17]

Answer:

867 tickets were sold because if you divide how much they earned by how much it cost you get 867

8 0
3 years ago
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