What’s the slope, y-intercept, and equation of this line??
1 answer:
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Answer:
7560 in^3
Step-by-step explanation:
Hello! The first thing that we must take into account to solve this problem is that the volume of any solid is equal to the transverse area by the height, in this case we must find the area of the trapezoid and then multiply it by the height
V=AL
V= Volume
A=area
L=height=9in
finding area of trapezoid
To know what each variable corresponds to, please see the attached file
finally multiply the area by the height of the box(9in)
V=AL
V=(840in^2)(9in)=7560in^3
the volume of the flower box is 7560 in^3
Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
_____
The problem statement gives no clue as to the currency equivalent of 100p.
Answer:
Step-by-step explanation:
According to the mentioned information, the sample space of the experiment is as follows: S= {7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18} The outcomes of the event E are as follows: E = {7, 8, 9, 10, 11, 12} Therefore, the outcomes of Ec can be calculated as:
= {xlx ∈ S , x ∉ E}
Ec = {13, 14, 15, 16, 17, 18}
The outcomes of are {13, 14, 15, 16, 17, 18} .
The obtained outcomes of the set Ec are {13, 14, 15, 16, 17, 18} . These are calculated by subtracting the outcomes of the event E from the elements of sample space S.
kindly check the image below for the concluding part if the solution to the question
