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2 years ago

(4200 + 75) + 5 = ( ? )+ (75+5) What would make it true?

Mathematics

2 answers:

geniusboy [140]2 years ago

8 0

Answer:

4200

Step-by-step explanation:

4280=(?)+80

So the answer is 4200

kirill115 [55]2 years ago

5 0

The answer would be 4200

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Use the definition of Taylor series to find the Taylor series, centered at c, for the function. f(x) = sin x, c = 3π/4

anyanavicka [17]

Answer:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Step-by-step explanation:

Given

$f(x) = \sin x\\$

$c = \frac{3\pi}{4}$

Required

Find the Taylor series

The Taylor series of a function is defines as:

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

We have:

$c = \frac{3\pi}{4}$

$f(x) = \sin x\\$

$f(c) = \sin(c)$

$f(c) = \sin(\frac{3\pi}{4})$

This gives:

$f(c) = \frac{1}{\sqrt 2}$

We have:

$f(c) = \sin(\frac{3\pi}{4})$

Differentiate

$f'(c) = \cos(\frac{3\pi}{4})$

This gives:

$f'(c) = -\frac{1}{\sqrt 2}$

We have:

$f'(c) = \cos(\frac{3\pi}{4})$

Differentiate

$f"(c) = -\sin(\frac{3\pi}{4})$

This gives:

$f"(c) = -\frac{1}{\sqrt 2}$

We have:

$f"(c) = -\sin(\frac{3\pi}{4})$

Differentiate

$f"'(c) = -\cos(\frac{3\pi}{4})$

This gives:

$f"'(c) = - * -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

So, we have:

$f(c) = \frac{1}{\sqrt 2}$

$f'(c) = -\frac{1}{\sqrt 2}$

$f"(c) = -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

becomes

$f(x) = \frac{1}{\sqrt 2} - \frac{1}{\sqrt 2}(x - \frac{3\pi}{4}) -\frac{1/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{1/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Rewrite as:

$f(x) = \frac{1}{\sqrt 2} + \frac{(-1)}{\sqrt 2}(x - \frac{3\pi}{4}) +\frac{(-1)/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{(-1)^2/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Generally, the expression becomes

$f(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Hence:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

3 0

2 years ago

During an experiment, Aika measured the time it took for a ball to roll down a ramp set at an angle. She measured that it took 1

schepotkina [342]

Answer:

11.725%

Step-by-step explanation:

Given that :

True value = 0.904 seconds

Measured time = 1.010 seconds

Experimental error :

(|measured value - True value | / true value) * 100%

(|1.010 - 0.904| ÷ 0.904) * 100%

= 0.106 / 0.904 * 100%

= 0.1172566 * 100%

= 11.725%

4 0

2 years ago

Read 2 more answers

Find k such that the equation kx^2+x+25k=0 has a repeated solution.

Paha777 [63]

Ill try to answer your question

4 0

3 years ago

What is the equation of the line that passes through (-5, -1) and is parallel to the line y=4x-6?

mr_godi [17]

Hello :
the equation all lines passes through (-5, -1) is :
y - (-1) = m(x -(-5)) m the slope
if this line parallal to the line y=4x-6 so : m= 4 (same slope )
the equation of the line that passes through (-5, -1) and is parallel to the line y=4x-6: is :
 y+1 =4(x+5)
y = 4x +19

8 0

2 years ago

Please can someone help me?

Feliz [49]

Answer:

weight of a water=0.5

spherical ball is filled With water=0.95.

so dear for

22\7*0.5*0.95=1.49

7 0

3 years ago