Answer:
i. Time = 2 hours.
ii. Average speed for the whole journey = 25 km/h
Step-by-step explanation:
Distance from Antville to Beetleton = 60 km
Mr. Caterpillar's speed = 30 km/h
Speed = 
⇒ time = 
= 
= 2
time = 2 hours
It would take Mr. Caterpillar 2 hours to travel from Antville to Beetleton at that speed.
On his return journey, his average speed is 20 km/h. Therefore;
average speed for the whole journey = 
= 
= 25
average speed for the whole journey = 25 km/h
now.. if you notice, the exponent for the 1st term, is dropping on each term subsequently, start with highest, 9 in this case, and drops drops drops, till on the last term, will be 0
the exponent for the second term, starts off at 0, and goes up up and up on each term
that part is simple... now, the coefficient for them
the first one will have a coefficient of 1, so we can take a closer look at the 2nd instead
the coefficient for the second is 1* 9/ 1
(1) the coefficient of the current term, (9) the exponent of the 1st term, and (1) the exponent of the 2nd term on the next term
for example, how did we get 84 for the 4th term? (36 * 7) / 3 = 84
and so on for all subsequent terms
Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer:
43.35 years
why?
From the above question, we are to find Time t for compound interest
The formula is given as :
t = ln(A/P) / n[ln(1 + r/n)]
A = $2500
P = Principal = $200
R = 6%
n = Compounding frequency = 1
First, convert R as a percent to r as a decimal
r = R/100
r = 6/100
r = 0.06 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06/1)] )
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06)] )
t = 43.346 years
(credit to VmariaS)
