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Ulleksa [173]
2 years ago
11

-2 • (-3)3 = ? i really need help, I’m struggling so much in math.

Mathematics
2 answers:
Ronch [10]2 years ago
6 0

Answer:

The answer would be 54

Step-by-step explanation:

nadezda [96]2 years ago
4 0

Let's break this statement into small pieces. Let's start with (-3)^{3}. This means -3 \times -3 \times -3 which is equal to -27 (-3 \times -3 = 9, 9 \times -3 = -27).

Note the following rules

  • - \times - = +
  • + \times + = +
  • - \times + = -
  • + \times - = -

Now let's solve the rest of the equation. -2 \cdot (-3)^{3} = -2 \cdot -27 (Note \cdot is the same as \times. = -2 \cdot -27, 54

The answer is 54

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2 years ago
Read 2 more answers
7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?
loris [4]

Answer: a. Radius of circle = \sqrt{85}

b. The equation of this circle : (x-3)^2+(y-10)^2=85

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = \sqrt{(12-3)^2+(12-10)^2}

Radius of circle = \sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}

i.e. Radius of circle = \sqrt{85}

b. Equation of a circle = (x-h)^2+(y-k)^2=r^2 , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= \sqrt{85} , we get

(x-3)^2+(y-10)^2=(\sqrt{85})^2

(x-3)^2+(y-10)^2=85

∴  The equation of this circle :(x-3)^2+(y-10)^2=85

6 0
3 years ago
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