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Ulleksa [173]
2 years ago
11

-2 • (-3)3 = ? i really need help, I’m struggling so much in math.

Mathematics
2 answers:
Ronch [10]2 years ago
6 0

Answer:

The answer would be 54

Step-by-step explanation:

nadezda [96]2 years ago
4 0

Let's break this statement into small pieces. Let's start with (-3)^{3}. This means -3 \times -3 \times -3 which is equal to -27 (-3 \times -3 = 9, 9 \times -3 = -27).

Note the following rules

  • - \times - = +
  • + \times + = +
  • - \times + = -
  • + \times - = -

Now let's solve the rest of the equation. -2 \cdot (-3)^{3} = -2 \cdot -27 (Note \cdot is the same as \times. = -2 \cdot -27, 54

The answer is 54

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Vsevolod [243]
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8 0
3 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
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Step2247 [10]

Answer:

Step-by-step explanation:

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4 0
2 years ago
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masya89 [10]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Using the rule (x+5, y+2) you would add 5 to the x value and 2 to the y value so the answer would be L' (7,5) M' (6,4) N' (9,6)
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