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2 years ago

If RS =8, ST =15 and RT =33. Find the value of x and RS. Use the number line below.

Mathematics

1 answer:

Brrunno [24]2 years ago

6 0

Answer:

value of x is 13 and RS = 18

hope this answer helps you dear...take.....care!

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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

4 0

3 years ago

How to write this in slope-intercept form? 8x + 10y = 40

worty [1.4K]

Answer:y=-4/5x+4

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please help with this fast

vitfil [10]

Answer:

repost it, I cant see all of the question

3 0

3 years ago

5x-2y=30 complete the missing value in the solution to the question (8, )

natali 33 [55]

Answer:

(8,5)

Step-by-step explanation:

5x-2y=30

lets substitute "8" as x and see where that takes us

5(8)-2y=30

40-2y=30

subtract 40 on both sides

-2y=-10

divide by "-2" on both sides

y=5

(8,5) is your answer

4 0

2 years ago

Read 2 more answers

I need help with this practice problem solving This is trigonometry from my ACT prep guide

Novay_Z [31]

Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:

$f(x)=A\cos (\frac{2\pi}{T}x)+b$

In the given case, you have:

A = 4

T = 3π/4

b = -3

By replacing you obtain:

$\begin{gathered} f(x)=4\cos (\frac{2\pi}{\frac{3\pi}{4}}x)-3 \\ f(x)=4\cos (\frac{8}{3}x)-3 \end{gathered}$

Hence, the answer is:

f(x) = 4cos(8/3 x) - 3

6 0

7 months ago