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dolphi86 [110]
2 years ago
13

Solve the system.

Mathematics
1 answer:
Alex777 [14]2 years ago
6 0

Answer:

{x,y,z} = {-18,4,2}

Step-by-step explanation:

Solve equation [2] for the variable  x  

x = -10y + 2z + 18

Plug this in for variable  x  in equation [1]

(-10y+2z+18) + 9y + z = 20

- y + 3z = 2

Plug this in for variable  x  in equation [3]

 3•(-10y+2z+18) + 27y + 2z = 58

   - 3y + 8z = 4

Solve equation [1] for the variable  y  

 y = 3z - 2

Plug this in for variable  y  in equation [3]

  - 3•(3z-2) + 8z = 4

   - z = -2

Solve equation [3] for the variable  z  

 z = 2

By now we know this much :

 x = -10y+2z+18

   y = 3z-2

   z = 2

Use the  z  value to solve for  y  

 y = 3(2)-2 = 4

Use the  y  and  z  values to solve for  x  

 x = -10(4)+2(2)+18 = -18

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3 years ago
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Solve For X<br> (see picture below) <br><br> thank you!
Mashutka [201]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
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5x^3 - 3x + 10 = 2x^2
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Therefore, options a and c can be solved using the quadratic formula.
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