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nalin [4]
3 years ago
6

Click on the measure that is equivalent to 3 kilometer

Mathematics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

optionc .3,000 metres.

hope it helps you.

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I need the description of how to draw a parallel line and a perpendicular line.
EleoNora [17]
How to Draw Parallel Lines:
1. Draw a straight line any length

2. Draw another straight line any length

(note : ensure the lines will never intersect)

They shall never horizontally or vertically.

How to Draw Perpendicular Lines:
1. Draw a straight line vertically

2. Draw a straight line horizontally

(note : length does not necessarily matter)

The two lines must cross at right angles to each other!!

With the parallel line instructions, simply just draw lines but, when given the slopes of two lines, you must get graphing paper or make your own, and graph it by plotting points and then getting a ruler and tracing it.

With the perpendicular lines it helps with showing a relation between situations along with given slopes. They shall intersect always and meet at a 90° angle. Use the equations and plot them then take a ruler and trace them and notice the intersection. Solve it yourself and see that the intersection and the answers you got are the same.
5 0
3 years ago
Find the measure of the following angles.<br><br> m &lt; LPM: <br><br> m <br> m <br> HELP ASAP‼️
Elena-2011 [213]

Answer:

kpl- 90°

jpk-52°

npm-142°

lpm-38°

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
GIVING 30 POINTS
FromTheMoon [43]

Answer:

A. 502.4 cm^3

Step-by-step explanation:

r=8/2=4  cm

V=pi*r^2*h=3.14*16*10=502.4 cm^3     (A)

7 0
4 years ago
Read 2 more answers
Use row operations to solve the system
TiliK225 [7]

Answer:

  (x, y, z) = (1, 12, 15)

Step-by-step explanation:

As with any set of linear equations, there are many possible routes to a solution. We might simplify the notation a bit by writing the coefficients in an augmented matrix. The columns, left to right, represent the coefficients of x, y, and z, in order, and the constant term.

The row operations we'll use are multiplying a row by a value and adding that result to another row, replacing the other row by the sum.

We can make things a little simpler by writing the second equation first. Then the augmented matrix we're starting with is ...

  \left[\begin{array}{ccc|c}4&-1&1&7\\1&1&-1&-2\\1&-3&2&-5\end{array}\right]

Adding the second row to the first, we get ...

  \left[\begin{array}{ccc|c}5&0&0&5\\1&1&-1&-2\\1&-3&2&-5\end{array}\right]

Dividing the first row by 5 gives ...

  \left[\begin{array}{ccc|c}1&0&0&1\\1&1&-1&-2\\1&-3&2&-5\end{array}\right]

Subtracting this from the second row, and again from the third row, we are left with ...

  \left[\begin{array}{ccc|c}1&0&0&1\\0&1&-1&-3\\0&-3&2&-6\end{array}\right]

Multiplying the second row by 3 and adding that to the third row, we get ...

  \left[\begin{array}{ccc|c}1&0&0&1\\0&1&-1&-3\\0&0&-1&-15\end{array}\right]

Subtracting the third row from the second gives ...

  \left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&12\\0&0&-1&-15\end{array}\right]

Finally, multiplying the last row by -1, we have the solution:

  \left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&12\\0&0&1&15\end{array}\right]

This matrix corresponds to the equations ...

  • x = 1
  • y = 12
  • z = 15

_____

The purpose of our choice of row operations is to make the diagonal elements 1 and the off-diagonal elements 0. That is how we end up with the final equations shown.

As we said, there are many ways to go about this. In general, one can ...

  • if necessary, swap rows until the diagonal term of interest is non-zero. If you are doing this using a computer program, generally you want the diagonal term to have the coefficient with the largest magnitude. When doing this by hand, you may want to arrange the rows to avoid fractions when you do the normalizing.
  • divide the row by the coefficient of the diagonal element to "normalize" the diagonal element to a value of 1
  • zero the other elements in that column by multiplying the row just normalized by the element in another row, then subtracting the product. (The 4th matrix shown above shows this for the first column.)
  • proceed to the next diagonal element and repeat the process until all diagonal elements are 1. If you cannot make all diagonal elements 1, then the system of equations does not have a unique solution. If any row becomes all zeros, the system is "dependent" and has infinite solutions. If a row is zeros except for the rightmost column, the system is "inconsistent" and has no solutions.
3 0
4 years ago
find the slope of the line through the points (2,-4) and (3,-4). is the line horizontal, vertical, or neither
Furkat [3]

Answer:

The slope of the line is 0 and the line is horizontal

Step-by-step explanation:

Given coordinates;

                      (2,-4) and (3,-4)

Unknown:

Slope of the line  = ?

Solution:

The slope of a line is the rise divided by the run. Mathematically, it is expressed as;

    Slope  = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }

x₁  = 2

x₂ = 3

y₁ = -4

y₂ = -4

 Insert the parameters and solve;

   Slope  = \frac{-4-(-4)}{3-2}   = 0

The slope of the line is 0 and the line is horizontal

8 0
4 years ago
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