3 years ago

Solve for y.8^3-3y=256^4y

1 answer:

3 0

$8^{3-3y}=256^{4y}\\\\(2^3)^{3-3y}=(2^8)^{4y}\\\\2^{3(3-3y)}=2^{8\cdot4y}\\\\2^{9-9y}=2^{32y}\iff9-9y=32y\\\\-9y-32y=-9\\-41y=-9\ \ \ \ /:(-41)\\\\y=\frac{9}{41}$

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What is the answer to the question. Solve for x

slega [8]

Answer:

Answer:

$x=\frac{75}2$

Step-by-step explanation:

Give letters, as in the attached image.

The triangles ABE and CDE are similars (AAA). In particular $AE:CE=BE:DE \rightarrow 46:30=(x+20):x \rightarrow 46x=30(x+20) \rightarrow 23x=15x+300 \rightarrow 8x=300\rightarrow x=\frac{75}2$