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natali 33 [55]
3 years ago
8

1. -15(-9)=

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0

Answer:

1. -24

2. 16

3. -33

4. -31

5. -64

6. -25

7. -1

8. 20

9. 2

Step-by-step explanation:

I attached an image explaining the rules. Hope this helped!

PIT_PIT [208]3 years ago
5 0

Answer:

01)135

02)16

03)-33

04)-31

05)-64

06)-25

07)-1

08)20

09)2

Step-by-step explanation:

Hope this will help you

Sadanavam1979 GREETINGS

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6 0
3 years ago
Hi :) how to do question 7 ?
Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

  • We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= \frac{-3}{2}x+8  
  • We khow that the points P and Q are two points in the cercle
  • Let Ω be the center of this cercle
  • we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
  • So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
  • Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
  • PΩ=\sqrt{(a-4)^{2}+(b-6)^{2}  } and QΩ=\sqrt{(a-8)^{2}+(b-2)^{2}   }
  • Let's substitute a by x and b by y
  • PΩ=QΩ we substitute each distance by its expression
  • After simplyfying the expressions we get finally : -12+8x-8y=0
  • now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
  • these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
  • we substitute a by 4 and y by 2 in PΩ to get the radius
  • we get r = \sqrt{(4-4)^{2}+(2-6)^{2}  } = 4
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5 0
3 years ago
Read 2 more answers
What is the domain of h?
Alexandra [31]

Answer:

{-2, -1, 1, 5, 6}

Step-by-step explanation:

The domain includes the five x-values (inputs):  {-2, -1, 1, 5, 6}

8 0
4 years ago
A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels
AURORKA [14]
\boxed {\boxed { \text {Distance = Speed x Time}}}

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x 
Distance = Time x Speed = 9x

<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

<u>Find the speed:</u>
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Answer: The spend of the two trains are 60 mph and 108 mph.
3 0
3 years ago
2 + 6x equals 1 - x​
melomori [17]

Answer:

x = -1/7

Step-by-step explanation:

simplify by bringing all the x to the left and all the constants to the right:

6x + x = 1 - 2

7x = -1  (divide by 7)

x = -1/7

5 0
4 years ago
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