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3 years ago

I need help with this geometry problem!

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

Line a and Line b are parallel.

∠x = 34° (alternative angles on a parallel line are equal)

Answer: ∠x = 34° (option C)

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Solve 18q – 2q2 = 0

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Answer:q=9

Step-by-step explanation:

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4 years ago

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Solve for X (picture included)

Fynjy0 [20]

Answer:

x = 41

Step-by-step explanation:

(2x+20) + (2x-4) = 180 degrees

4x+16 = 180 degrees

4x = 164

x = 41

The two sides are supplementary and add up to 180 degrees.

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3 years ago

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Troyanec [42]

Answer:

535572

Step-by-step explanation:

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3 years ago

Which parabola has the graph shown? I think the answer is C. however, I'm not 100% sure.

NemiM [27]

$x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex$

We have the vertex (-4, -1), therefore we have:

$x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2$

7 0

4 years ago

Which expression represents the distance between the points (11, 4) and (5,8)?

antiseptic1488 [7]

Answer:

$\displaystyle d = 2\sqrt{13}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(5-11)^2+(8-4)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-6)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{36+16}$
[√Radical] Add: $\displaystyle d = \sqrt{52}$
[√Radical] Simplify: $\displaystyle d = 2\sqrt{13}$

4 0

3 years ago