X=-.5, it’s less than 0, and concave up & increasing in this situation are the same.
Answer:
p = -1/2
Step-by-step explanation:
(6 × p) + 3
= 6p + 3
6p = -3
p = -3/6
p = -1/2
Answer:
whats the question
Step-by-step explanation:
Answer:
See attachment for graph
Step-by-step explanation:
<em>See comment for correct question</em>
Given

Required
The corresponding points on 
On the graph, we have:





First, we solve for b in 
Using laws of logarithm, the equivalent of the above is:

implies that:


Rewrite as:

So, the equation
becomes:

Using the same values of x, we have:





<em>See attachment for graph</em>
25(3x-y)²-16(5x+3y)²=25(9x²-6xy+y²)-16(25x²+30xy+9y²)=
=225x²-15xy+25y²-400x²-480xy-144y²=-175x²-630xy-119y²