Answer:
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE))/12
Explanation:
Adds all of the Monthly Expenses : SUM(PUT RANGE OF MOTHLY EXPENSES HERE)
Multiplies the result by 12: *12
Then adds all of the Yearly Expenses to the product of Steps 1 and 2 : SUM(PUT RANGE OF YEARLY EXPENSES HERE)
Divides this new sum by 12: /12
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE)/12)
DHCP snooping is a mitigation technique<span> to </span>prevent rogue<span> DHCP </span>servers <span>from </span>providing false IP configuration parameters to clients. DHCP snooping<span> is a security feature that acts like a firewall between untrusted hosts and trusted </span>DHCP<span> servers. It is</span><span> a series of techniques applied to improve the security of a </span>DHCP<span> infrastructure. </span>
Answer:
In curriculum, a vision of knowledge, the role of the educator and a concept of the process of education are all present. In this sense, Stenhouse suggests that the role of teachers and professors is fundamental in the elaboration and implementation of curriculum.
<h2>answer:</h2>
Synchronized method is used to lock an object for any shared resource. When a thread invokes a synchronized method, it automatically acquires the lock for that object and releases it when the thread completes its task.','.
Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
