Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
Multiply equation B by 2.
Multiply equation A by 2
Multiply equation B by 3.
Multiply equation A by -3
Answer: D
Answer:
15.5
Step-by-step explanation:
The equation to find area is Length × Width= Area
we have the area and the length, 12.5 × width= 293.75
to find the width, you will have to reverse engineer and divide the area by the length instead.
193.75 ÷ 12.5 =15.5
just to double check, 15.5 × 12.5 = 193.75
the width is 15.5
Answer:
Option B, At least three will have the transponder
Step-by-step explanation:
<u>Step 1: Find the probability in 6 cars</u>
6 * %80 or 6 * 0.8
4.8
Answer: Option B, At least three will have the transponder
Let the two numbers be x and y.
We have x+y=45
⇒ y= 45-x.
The two numbers multiply and get 121, so we have another equation:
x*y = 121 (1)
Plug y= 45-x in (1), we have:
x* (45-x)=121
⇒ 45x - x^2 = 121 (distributive property)
⇒ x^2 - 45x = -121 (multiply -1 on both sides)
⇒ x^2- 45x + 121= 0
⇒ x= 42.128 or x= 2.872
y= 45- 42.128= 2.872
or y= 45- 2.872= 42.128.
Because it does not matter what number, x or y, is larger, the two numbers are 2.872 and 42.128.
Hope this helps~
