I have a slope of -4 (m=-4), would that be negative four over positive one or would that be negative 4 over negative one?

Given the functions, f ( x ) = x - 8 and g ( x ) = x2 x - 1, perform the indicated operation. when applicable, state the domain

kondor19780726 [428]

(fg)(x)= x³ - 7x² - 9x + 8

domain is (-∞,∞)

Given: f(x)= x-8, g(x)= x² +1x - 1

To find (fg)(x) we multiply f(x) and g(x)

(fg)(x) = f(x) * g(x)

(fg)(x)= (x-8) (x²+x-1)

(fg)(x)= x³ + x² - x - 8x² - 8x +8

(fg)(x)= x³ - 7x² - 9x + 8

we know, domain for all cubic function is set of all real numbers

domain is (-∞,∞)

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6 0

11 months ago

!!!!!!!!!!!!!! Pleasee

hammer [34]

Answer:

i dont know can you turn your sceen so i can see it better

Step-by-step explanation:

4 0

2 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

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4 0

2 years ago

Can someone help me with this i have been trying for hours and i actually got the wrong answer so can you help me understand by

kap26 [50]

Answer:

C

Step-by-step explanation:

We are given that FGH is a triangle, which means that...

Angle F + Angle G + Angle H = 180

Start by substituting the given angle measurements into the equation:

4x+2+13x-7+3x+5=180

Combine like terms

20x=180

Divide both sides by 20 to isolate x

x=9

Plug 9 back in for x to solve for each angle

Angle F = 4(9)+2=36+2=38

Angle G = 13(9)-7=117-7=110

Angle H = 3(9)+5=27+5=32

7 0

2 years ago

Read 2 more answers

**** HELP*****

Mademuasel [1]

Birmingham and Montgomery both have a state sales tax rate of 4 percent and a local tax rate of 6 percent – although the report notes that part of Birmingham lies in Shelby County, meaning the combined rate is only 9 percent in some parts of the city.

4 0

2 years ago

Read 2 more answers