GIVING BRAINLIST!GIVING BRAINLIST AND 100 POINTS PLEASEE HELP MEE ASAP!! Using the H-R diagram provided, plot points on the give
n graph for the stars you researched. Use the circle tool to plot a point. Use the text box tool to label each point with the appropriate star name. THE STARS: Sun, Alpha Centauri A, Sirius B, Barnard’s Star, Sirius A, and Proxima Centauri. (PLEASE LABEL THE CHART CLEARLY!!)
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Explanation:
The given reaction is as follows.
As it is known that number of moles equal mass divided by molar mass. Molar mass of methane is 16 g/mol.
Hence, No. of moles =
=
= 0.493 mol
Molar mass of oxygen is 32 g/mol.
Hence, its number of moles =
=
= 0.45 mol
As, it is shown from the reaction that 1 mole of methane needs 2 mole of oxygen.
Therefore, 0.493 mol of methane needs equals 0.9 moles of oxygen.
As there is only 0.45 moles of oxygen for the reaction. So, it means that oxygen is the limiting reagent.
Hence, for 0.45 moles of oxygen, methane required is as follows.
= 0.225 moles
So, 0.225 moles of methane is equal to = 3.6 g
As, 3.6 g of methane reacts with oxygen. Therefore, amount of methane remains is calculated as follows.
(7.9 g - 3.6 g) = 4.3 g
Thus, we can conclude that the minimum mass of methane that could be left over by the chemical reaction is 4.3 g.