Answer: D
Explanation:
I assume you meant
.
- The atomic mass of potassium is 39.0983 g/mol.
- The atomic mass of sulfur is 32.065 g/mol.
- The atomic mass of oxygen is 15.9994 g/mol.
So, the formula mass of potassium sulfate is 2(39.0983)+32.065+4(15.9994)=174.2592 g/mol.
So, 5.00 moles have a mass of (5.00)(174.2592), which is about <u>870 g</u>
Answer:
C - no antibodies
Explanation:
I dont think there is any blood type without antibodies
Weight of the balloon = 2.0 g
Six weights each of mass 30.0 g is added to the balloon.
Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g
Density of salt water = 1.02 g/mL
Calculating the volume from mass and density:
![182g*\frac{mL}{1.02g} =178mL](https://tex.z-dn.net/?f=182g%2A%5Cfrac%7BmL%7D%7B1.02g%7D%20%3D178mL)
Converting the volume from mL to cubic cm:
![178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}](https://tex.z-dn.net/?f=178%20mL%20%2A%20%5Cfrac%7B1cm%5E%7B3%7D%20%7D%7B1mL%7D%20%3D178cm%5E%7B3%7D)
Assuming the balloon to be a sphere,
Volume of the sphere =
π![r^{3}](https://tex.z-dn.net/?f=r%5E%7B3%7D)
![178 cm^{3} = \frac{4}{3}(\frac{22}{7})r^{3}](https://tex.z-dn.net/?f=178%20cm%5E%7B3%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%28%5Cfrac%7B22%7D%7B7%7D%29r%5E%7B3%7D)
r = 3.49 cm
Radius of the balloon = 3.49 cm
Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm
Answer: The partial pressure of
is 1.86 atm
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_c](https://tex.z-dn.net/?f=K_c)
The given balanced equilibrium reaction is,
![PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)](https://tex.z-dn.net/?f=PCl_5%28g%29%5Crightleftharpoons%20PCl_3%28g%29%2BCl_2%28g%29)
Pressure at eqm. 0.973 atm 0.548atm x atm
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{(p_{PCl_3}\times (p_{Cl_2})}{(p_{PCl_5})}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%28p_%7BPCl_3%7D%5Ctimes%20%28p_%7BCl_2%7D%29%7D%7B%28p_%7BPCl_5%7D%29%7D)
Now put all the given values in this expression, we get :
![1.05=\frac{(0.548)\times (x)}{(0.973)}](https://tex.z-dn.net/?f=1.05%3D%5Cfrac%7B%280.548%29%5Ctimes%20%28x%29%7D%7B%280.973%29%7D)
By solving the term 'x', we get :
x = 1.86 atm
Thus, the partial pressure of
is 1.86 atm