Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonatio
n of alcohol and oxygen to form an oxonium ion.
Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction.
Dehydration of 3-methyl-2-butanol forms one major and two minor organic products. Draw the structures, including hydrogen atoms, of the three organic products of this reaction.
1 answer:
Answer:
Most substituted alkene is produced as a major product
Explanation:
- Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
- Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
- Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
- Reaction mechanism has been shown below.
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The hydrogen deficiency index( HDI) of strigol is = 10
<h3>How to calculate HDI:</h3>The hydrogen deficiency index is used to measure the number of degree of unsaturation of an organic compound.
Strigol is an example of an organic compound because it contains carbons and hydrogen.
To calculate the HDI using the molecular formula given (C19H20O6) the formula for HDI is used which is:
where C = number of carbon atoms = 19
n= number of nitrogen atoms = 0
h= number of hydrogen atoms = 20
X = number of halogen atoms = 0
Note that oxygen was not considered because it forms two bonds and has no impact.
There for HDI =
HDI=
HDI =
HDI = 10
Therefore, the hydrogen deficiency index of strigol is = 10
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