<u>Given</u>:
Given that the side of the regular polygon is 16 feet.
We need to determine the area of the polygon.
<u>Area of the polygon:</u>
The area of the polygon can be determined using the formula,
![Area =\frac{s^2 n}{4 \ tan \frac{180}{n}}](https://tex.z-dn.net/?f=Area%20%3D%5Cfrac%7Bs%5E2%20n%7D%7B4%20%5C%20tan%20%5Cfrac%7B180%7D%7Bn%7D%7D)
where n is the number of sides,
s is the side length.
Substituting n = 3 and s = 16, we get;
![Area =\frac{16^2 (3)}{4 \ tan \frac{180}{3}}](https://tex.z-dn.net/?f=Area%20%3D%5Cfrac%7B16%5E2%20%283%29%7D%7B4%20%5C%20tan%20%5Cfrac%7B180%7D%7B3%7D%7D)
Simplifying, we get;
![Area =\frac{(256) (3)}{4 \ tan \ 60}](https://tex.z-dn.net/?f=Area%20%3D%5Cfrac%7B%28256%29%20%283%29%7D%7B4%20%5C%20tan%20%5C%2060%7D)
![Area = \frac{768}{6.928}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B768%7D%7B6.928%7D)
Dividing, we get;
![Area = 110.85](https://tex.z-dn.net/?f=Area%20%3D%20110.85)
Rounding off to the nearest tenth, we have;
![Area = 110.9](https://tex.z-dn.net/?f=Area%20%3D%20110.9)
Thus, the area of the regular polygon is 110.9 square units.
Answer:
A.
Step-by-step explanation:
It has the correct slopes and y-intercepts.
For this case we have the following relationship:
P1V1 = P2V2
Clearing volume 2 we have:
V2 = (P1 / P2) * (V1)
Substituting values we have:
V2 = (5.1 / 1.0) * (350)
V2 = 1785 mL
Answer:
this gas would occupy 1785 mL at 1.0atm
Answer:
x < -4
Step-by-step explanation:
-3x > 12
Divide both parts with -3.
-3x/-3 > 12/-3
x < -12/3
x < -4