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Andrew [12]
3 years ago
14

You are standing on a small fire tower 50 feet from a tree. You notice a squirrel in the tree. You measure the angle of depressi

on to the base of the tree to be 52∘. The squirrel is at an angle of elevation of 21∘. How many feet off the ground is the squirrel?

Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

44.81 feet

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ACD

Find the length side AC (height of the small fire tower)

tan(52^o)=\frac{AC}{50} ---> by TOA (opposite side divided by the adjacent side)

Solve for AC

AC=tan(52^o){50}

AC=64\ ft

step 2

In the right triangle ABE

Find the length side AB

tan(21^o)=\frac{AB}{50} ---> by TOA (opposite side divided by the adjacent side)

solve for AB

AB=tan(21^o){50}

AB=19.19\ ft

step 3

How many feet off the ground is the squirrel?

Subtract the length side segment AB from the length side segment AC

so

64-19.19=44.81\ ft

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The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

                 Given diagram is combination of Rectangle and Semi circle.

Step:1

         Res the attachment,

                      Area of given diagram = Area of A + Area of B..............(1)

Step:2

         For A,

         The A section in the given diagram is semi circle,

                     Diameter of semi circle = Total distance - ( 2+3)

                                          ( ∵ 2, 3 are top distance in the given diagram)

                                                             = 10 - 5

                                        Diameter, d = 5 cm

                                             Radius, r = \frac{d}{2}

                                                          r = \frac{5}{2}

                                                         r = 2.5 cm

                                          Area, A_{A}  = \frac {\pi r^{2} }{2}........................(2)

                                                    A_{A}  = \frac {\pi (2.5)^{2} }{2}  

                                                           = \frac {\pi ( 6.25) }{2}

                                                           = \frac{19.63}{2}

                                                     A_{A} = 9.8174 cm^{2}

Step:3

               For B,

               Area of rectangle is,

                                                      A_{B} =lb.....................(3)

              Where, l - Length = 10 cm

                          b - Width = 2 cm

              Equation (3) become,

                                                            = (10)(2)

                                                            = 20

                                    Area of B, A_{B} = 20 cm^{2}

Step:4

               From the equation (1),

                               Area of given diagram = 20+ 9.81747

                                                            Area = 29.817 square centimeters

Result:

            The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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