<span>Area = (1/2)(533 ft)(525 ft) sin(53) = 111739 square feet</span>
243 counselors will be there
I would go with then answer 168
Because if 12 of 180 has spots then you would subtract 12 to get how many will not have spots ....thats how I got the answer
Hope I helped Pls mark me as brainliest
If the number of visitors on Friday, Saturday, and Sunday is x, x + 500, and x + 250. Then the total number of visitors will be 3x + 750.
<h3>What is Algebra?</h3>
Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.
Tanisha's website had x visitors on Friday.
On Saturday, it had 500 more visitors than it did on Friday. That is x + 500
The total number of visitors on Friday and Saturday was twice the number on Sunday. That is (2x + 500)/2
Then the total number of the visitors will be
→ Friday + Saturday + Sunday
Then we have
![\rm \rightarrow x + x + 500 + \dfrac{2x + 500}{2}\\\\\rightarrow 2x + 500 + x + 250\\\\\rightarrow 3x + 750](https://tex.z-dn.net/?f=%5Crm%20%5Crightarrow%20x%20%2B%20x%20%2B%20500%20%2B%20%5Cdfrac%7B2x%20%2B%20500%7D%7B2%7D%5C%5C%5C%5C%5Crightarrow%202x%20%2B%20500%20%2B%20x%20%2B%20250%5C%5C%5C%5C%5Crightarrow%203x%20%2B%20750)
More about the Algebra link is given below.
brainly.com/question/953809
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Answer:
The distance between the cruise ship and the sail boat is 517 feet.
Step-by-step explanation:
The cruise ship is 236 feet tall, and the sailboat is 236 tall; this means the distance between the top of the cruise ship and the top of the sail boat is
236 feet - 27 feet = 209 feet.
We also know that the angel of depression from the top of the cruise ship to the bottom of the cruise ship is 22°. This forms a right triangle as shown in the figure attached.
Now from trigonometry we get:
![tan \: \theta = \dfrac{209}{d}](https://tex.z-dn.net/?f=tan%20%5C%3A%20%5Ctheta%20%3D%20%5Cdfrac%7B209%7D%7Bd%7D)
![d= \dfrac{209}{tan\:\theta }](https://tex.z-dn.net/?f=d%3D%20%5Cdfrac%7B209%7D%7Btan%5C%3A%5Ctheta%20%7D)
![\boxed{d=517ft}](https://tex.z-dn.net/?f=%5Cboxed%7Bd%3D517ft%7D)
The distance between the cruise ship and the sailboat is 517 feet.