Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure
It’s (d) because if one solution to a quadratic function g is the solution given then the other solution must be it’s complex conjugate which is d.
<span>None, because with triangles the sum of the two shorter side lengths (5 m + 5 m) needs to be equal to or greater than the length of the longest side (15 m). In this case, the sum of the two shorter sides is 10 m, which is less than 16 m, so a triangle cannot form.</span>
-w is the variable, so our goal is to get it on the left side of the equal sign and keep the 15 on the right side.
distribute the -2 to each term inside the parentheses. the equation should now look like this:
2w - 6 = 15
now, we must transpose the -6 to the other side of the equation. remember, we're moving it across the equal sign, so it becomes a positive 6.
2w = 21
now divide each side of the equation by 2 so the variable is alone.
w = 10.5
hope i helped!