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Dvinal [7]
3 years ago
5

What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

Mathematics
2 answers:
xxMikexx [17]3 years ago
3 0
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)

we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment  is 3√2

see the attached figure

creativ13 [48]3 years ago
3 0

Answer: 3\sqrt{2}

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