What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

Mathematics

2 answers:

xxMikexx [17]3 years ago

3 0

Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure

creativ13 [48]3 years ago

3 0

Answer: $3\sqrt{2}$

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