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Marina86 [1]
2 years ago
8

Someone help me please

Mathematics
1 answer:
Maslowich2 years ago
6 0
It’s (d) because if one solution to a quadratic function g is the solution given then the other solution must be it’s complex conjugate which is d.
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Write the equation of a line perpendicular to 3x + 4y = 9 that passes through (8, - 4)
Arisa [49]

keeping in mind that perpendicular lines have <u>negative reciprocal</u> slopes, let's find the slope of 3x + 4y = 9, by simply putting it in slope-intercept form.


\bf 3x+4y=9\implies 4y=-3x+9\implies y=-\cfrac{3x+9}{4}\implies y=\stackrel{slope}{-\cfrac{3}{4}}x+\cfrac{9}{4} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{4}{3}}\qquad \stackrel{negative~reciprocal}{+\cfrac{4}{3}}\implies \cfrac{4}{3}}


so we're really looking for the equation of a line whose slope is 4/3 and runs through 8, -4.


\bf (\stackrel{x_1}{8}~,~\stackrel{y_1}{-4})~\hspace{10em} slope =  m\implies \cfrac{4}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{4}{3}(x-8) \implies y+4=\cfrac{4}{3}x-\cfrac{32}{3} \\\\\\ y=\cfrac{4}{3}x-\cfrac{32}{3}-4\implies y=\cfrac{4}{3}x-\cfrac{44}{3}

5 0
3 years ago
A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts
Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

8 0
3 years ago
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Find a formula for the nth term of the sequence 1 -4 9 -16 25
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