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Ivenika [448]
2 years ago
9

Solve –16t² +144= 0 to find the number of seconds, t, it takes for an object dropped from 144 ft above the ground to hit the gro

und. Enter the correct values in the boxes to find the solution
- 16 {t}^{2}  + 14 = 0
- 16 {t}^{2}  + 144 - () = 0 - ()
- 16 {t}^{2}  = ()
\frac{ - 16}{?}  {t}^{2}  = ()
{t}^{2}  = ()



​

Mathematics
1 answer:
Vlad1618 [11]2 years ago
6 0

Answer:

h(t) = -16t2 + 144

h(1) = -16(12) + 144 = 128 ft

h(2) = -16(22) + 144 = 80 ft

h(2) - h(1) = 80 - 128 = -48 ft

It fell 48 ft between t = 1 and t = 2 seconds.

It reaches the ground when h(t) = 0

0 = -16t2 + 144

t = √(144/16) s = 3s

It reaches the ground 3s after being dropped.

Step-by-step explanation:

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3 0
3 years ago
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6. For what value of p, the binary number 110P/2 represents 25?​
lions [1.4K]

Step-by-step explanation:

25 as binary number is

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1 year ago
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8x + 2+ 4y; x = 9, y = 2
Alchen [17]

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4 0
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Thx u if u get the answer
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