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Reptile [31]
2 years ago
12

Write the ratio as a fraction in simplest form. 27 to 72

Mathematics
1 answer:
Mademuasel [1]2 years ago
4 0

Answer: The ration for 27:71, would be 3/8. Hope this helps!

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In the triangle below, the value of a is 12.6.<br><br> True<br><br> False
aev [14]

Answer:

True

Step-by-step explanation:

Formula

Tan(x) = opposite / adjacent

Givens

x = 42

adjacent = 14

opposite = ?

Solution

Tan(42) = opp/14                     Find tan(42)

Tan(42) = 0.900404

0.900404 = opp/ 14                Multiply both sides by 14

14 * 0.900404 = opp/14 * 14   Simplify the left

12.6 rounded  = opp

a = 12.6


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3 years ago
#4 NEAD HELP SOLVE THIS QUESTION ASAP
sergiy2304 [10]
C. 118.2

1 and 2 make a complimentary angle, so 2=118.2

2 and 6 are corresponding, so angle 2=angle 6 (118.2 = 118.2)
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What is the length of the hypotenuse of a right triangle that has sides measuring 12 cm and 35 cm
Westkost [7]
The measurement is 37 cm
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Tomas correctly spelled 18 out of 20 words oh his last spelling quiz. What decimal represents the portion of the words that Toma
Alborosie
The decimals that represent the portions of the words that Tomas spelled correctly is 0.9 or 0.90.
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fenix001 [56]

When you see the 'line' is increasing starting from 0 to 2 hours, this indicates that the person on the graph is riding up a hill. This is known as positive acceleration or constant positive acceleration.

Where you see the 'line' stays the same 2 to 5 hours, this can indicate that the bike rider is doing one or two things. One thing the biker could be doing is taking a rest, and the other could be that the biker is riding at a leveled ground. This could be known as having constant velocity or zero acceleration.

Finally, where the 'line' is decreasing from 5 to 6 hours, this can indicate that biker is riding, possibly, down a hill. This is known as negative acceleration.

And of course, when the 'line' is going up again from 6 to 7 hours, this indicates that the biker is riding up a hill or increasing his speed. This is known as positive acceleration or constant positive acceleration.

•

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- Marlon Nunez

4 0
3 years ago
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