Answer:
<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>
Step-by-step explanation:
The question is
<em>
There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>
<em />
Givens
- The total amount of chocolate candies is 11.73 kilograms.
- First costumer bought 48 dag of candies. (1 kg equals 100 dags)
- Second costumer bougth 4/5 of the remaining.
- Another three costumers bought the same amount of candy.
Let's transform 48 dag to kilograms.

Therefore, the first costumer bought 0.48 kilograms of candies.
The remaining amount is: 
Now, we need to multiply the remaining amount of candies with 4/5

Therefore, the second costumer bought 9 kilograms of chocolate candies.
At last, we need to find the new remaining part of candies, which is

Therefore, the last costumers got 2.25 kilograms of chocolate candies.
Answer:
7/3
Step-by-step explanation:
as it is a reciprocal you must flip the fraction so you can get your answer i hope this helped C:
Answer:
Try solving 6(n-5)-2.
Step-by-step explanation:
I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.