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asambeis [7]
4 years ago
6

How many solutions can be found for the linear equation? 4(x + 5) - 5 = 8x + 18/ 2

Mathematics
2 answers:
mylen [45]4 years ago
6 0

Answer: The correct option is A.

Explanation:

The given equation is,

4(x+5)-5=\frac{8x+18}{2}

Multiply both sides by 2.

2[4(x+5)-5]=\frac{8x+18}{2}

8(x+5)+2(-5)=8x+18

8x+40-10=8x+18

8x+30=8x+18

Subtract both sides by 8x.

30=18

This statement is false for any value of x, therefore the system of equation have no solution and option A is correct.

iVinArrow [24]4 years ago
4 0

Answer:

Option A is correct

No solutions

Step-by-step explanation:

The distributive property says that:-

a \cdot (b+c) = a\cdot b+ a\cdot c

Given the equation:

4(x+5)-5 = \frac{8x+18}{2}

Using distributive property we have;

4x+20-5 = \frac{8x+18}{2}

⇒4x+15= \frac{8x+18}{2}

Multiply both sides by 2 we have;

8x+30 = 8x+18

Subtract 8x from both sides we have;

30=18 False.

For any value of x, there is no solutions for the given system of equation

Therefore, No solution can be found for the linear equation

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935, 91

Step-by-step explanation:

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3 years ago
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3 years ago
What is the rate of change (8,13), (-13,-15)
3241004551 [841]

Answer:

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Step-by-step explanation:

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Hope this helps!

5 0
4 years ago
In a square, doubling every side increases the area by 27 units. What is the length of side of the newly formed square? a) 3 b)
MatroZZZ [7]
<h3>Answer:  B) 6</h3>

===========================================================

Explanation:

x = original side length

2x = double the side length

The old area is x^2. The new square area is (2x)^2 = 4x^2

new area = (old area) + 27

4x^2 = x^2 + 27

4x^2-x^2 = 27

3x^2 = 27

x^2 = 27/3

x^2 = 9

x = sqrt(9)

x = 3

The old original square has a side length of 3 units.

The new larger square has a side length of 2x = 2*3 = 6 units which is the final answer (choice B)

old area = 3^2 = 9

new area = 6^2 = 36

The jump from 9 to 36 is +27 to help confirm the answer.

6 0
2 years ago
Read 2 more answers
Can someone help me with questions 22-24? please and thank you
Kryger [21]
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