Answer:
<h3>Part A</h3>
The graph is non-linear as it is not a continuous straight line (with only one slope).
<h3>Part B</h3>
<u>Increasing</u>: the y-value increases as the x-value increases
<u>Constant</u>: the y-value stays the same as the x-value changes
<u>Decreasing</u>: the y-value decreases as the x-value increases
Therefore,
- Increasing segment: Between 0 and 2 seconds
- Constant segment: Between 2 and 3 seconds
- Decreasing segment: Between 3 and 5 seconds
<h3>Part C</h3>
For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second. The ant then stops.
Your answer would most likely be
B
Hello!
Since this is a reflection, then the new figure has to be congruent since we're not changing the size or the shape.
Now, (x, y) is located in the First Quadrant, whereas (x, -y) is located in the Fourth Quadrant. If we're going from the First Quadrant to the Fourth Quadrant, then this has to be a reflection across the x-axis.
The correct answer is "Yes, ΔP'Q'R is a reflection of ΔPQR over the x-axis." :)
Answer:
x= 16
Step-by-step explanation:
12(x-4) = 144
(Divide 12 both sides)
x - 4 = 12
(add 4 both sides)
x = 16