The answer is C. |-31|=3
The absolute value of -31 should’ve been 31 not 3
If you would like to solve the following system, you can calculate this using the following steps:
y = x - 20
y = 6 * x
_________
6 * x = x - 20
6 * x - x = -20
5 * x = -20 /5
x = -4
y = 6 * x = 6 * (-4) = -24
If you would like to solve the following system, you can calculate this using the following steps:
y = x + 20
y = 6 * x
_________
6 * x = x + 20
6 * x - x = 20
5 * x = 20 /5
x = 4
y = 6 * x = 6 * 4 = 24
Answer:
1 Use Difference of Squares:
a^2-b^2=(a+b)(a−b).
10(x^2-4^2)
2 Simplify 4^2 to 16
10(x^2 −16)
3 Expand by distributing terms.
10x^2 −160
Step-by-step explanation:
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§ALEX§
Answer: 9
Step-by-step explanation:
From doing the math I think it should be 9
Answer:
a) integral = 24.72
b) |Error| ≤ 0.4267
Step-by-step explanation:
a)
The integral:

can be approximated with the midpoint rule, as follows:
6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72
(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)
b)The error bound for the midpoint rule with <em>n</em> points is:
|Error| ≤ K*(b - a)^3/(24*n^2)
where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|
Given that -5 ≤ f''(x) ≤ 1, then K = 5. Replacing into the equation:
|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267