n = 4 means that you are going to divide the area in 4 equal parts, that means that the size of the intervals is [20-4] / 4 = 16 / 4 = 4.
Now you can estimate the area from 4 to 20, by adding the area from 4 to 8 + the area from 8 to 12 + the area from 12 to 16 + the area from 16 to 20
And estimate each small area by a rectangle or a trapezoid.
As a trapezoid, area of each region is [f(x) + f(x+4)] /2 [x +4 - x] = [f(x) + f(x+4)] /2 [4] =
=[f(x) + f(x+4)] / 8
Area from 4 to 8: [11 +25] / 8 = 4.50
Area from 8 to 12: [25+16]/8 = 5.125
Area from 12 to 16 = [16+9]/8 = 3.125
Area from 16 to 20 = [9+31]/8 = 5.00
Total area = 17.75
Answer: 17.75
Answer:
5
Step-by-step explanation:
12+12+12= 36
36-7= 29
3+3+3=9
29-9=20
20÷4=5
So to begin, you need to find x and y. If you have answer options, plug those in. If you don't, your toast. Just kidding :)
So, your answer would be y3=13. I think you can handle the rest. 3 * what equals 13?
X = 58
The angle directly across from the 32 is also 32 degrees because it uses the same lines at the same angles. That's the Vertical Angles Theorem. The line straight across means that is 180 degrees, which is already split in half by the visible 90 degree angle (given by the box in the corner). Since all the angles are on the same side of the line, the 180 degree angle, they should add up to equal 180 degrees. Also, since 90 is half of 180, the 32 degree angle and the x angle should just add up to equal 90 degrees. So, 90 minus 32 equals 58.
Answer: x ≥ 7
Step-by-step explanation:
You have to square both sides of the equation. You can manipulate an equation or function any way imaginable as long as it is done equally and helps the problem become easier. If we square this, the radical will cancel and we will get two trinomials equal to each other.
We can see the two expressions are exactly equal to each other. All real numbers are solutions, besides a few. These few are when the radical is equal to a negative number. So lets set up an inequality stating that the radical must be greater than or equal to 0.
