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frosja888 [35]
3 years ago
10

The function f(x) = –x3 + 2x2 – x + 5 is graphed on a coordinate grid. Which statements accurately describe the end behavior of

the graph of the function?
Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0

Answer: The true statements about the graph of the function are:

The range of the function is {y : y ≤ 6} ⇒ 2nd

The function is increasing over the interval (–∞ , –2) ⇒ 3rd

The function has a positive y-intercept ⇒ 5th

Step-by-step explanation: Lets explain how to solve the problem

- The function f(x) = -x² - 4x + 2 is a quadratic function represented

 graphically by a downward parabola with maximum vertex

∵ The form of the quadratic function is f(x) = ax² + bx + c

∵ The coordinates of the vertex of the parabola are (h , k) where

  h = -b/2a and k = f(h)

∵ a = -1 , b = -4

∴ h = -(-4)/2(-1) = 4/-2 = -2

∵ k = f(h)

∴ k = -(-2)² - 4(-2) + 2 = -(4) - (-8) + 2

∴ k = -4 + 8 + 2 = 6

∴ The vertex of the parabola is (-2 , 6)

* Look to the attached figure to find the true statements

∵ The greatest value of the function is 6 ⇒ y-coordinate of the vertex

∵ The range of the function is the values y-coordinates of the points

 on the parabola

∴ The range of the function is {y : y ≤ 6}

- The domain of the function is {x : x ∈ R} or (-∞ , ∞)

∵ The value of y increasing after -∞ to the x-coordinate of the vertex

∵ x-coordinate of the vertex is -2

∴ The function is increasing over the interval (–∞ , –2)

- The parabola intersect the y-axis at point (0 , 2)

∵ The y-intercept is the intersection between the parabola and the

  y-axis

∵ The parabola intersect the y-axis at point (0 , 2)

∴ The y-intercept is 2

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Answer:

μ = 235.38

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Step-by-step explanation:

Assuming the table is as follows:

\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]

This is an example of grouped data, where a range of values is given rather than a single data point.  First, find the total frequency.

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μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

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μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

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The standard deviation is:

σ = 234.54

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