Answer:
2(x+5) = 2x+10
Step-by-step explanation:
I'm assuming you can use any possible combination of two equivalent numerical expressions for your question.
2(x+5) = 2x+10
2 times x is 2x. 2 times 5 is 10. So, you get 2x+10
The number of outcomes possible from flipping each coin is 2, therefore;
- The expression that can be used to find the number of outcomes for flipping 4 coins is: 2•2•2•2
<h3>How can the expression for the number of combinations be found?</h3>
The possible outcome of flipping 4 coins is given by the sum of the possible combinations of outcomes as follows;
The number of possible outcome from flipping the first coin = 2 (heads or tails)
The outcomes from flipping the second coin = 2
The outcome from flipping the third coin = 2
The outcome from flipping the fourth coin = 2
The combined outcome is therefore;
Outcome from flipping the 4 coins = 2 × 2 × 2 × 2
The correct option is therefore;
Learn more about finding the number of combinations of items here:
brainly.com/question/4658834
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Mrs.Lombardo.<span>if you do the math out, 4/5 and 2/3 give you an LCD (Least Common Denominator) of 15, so this means 4/5 = 12/15, and 2/3 = 10/15. 4/5 is greater than 2/3. </span>
Answer:
The bearing needed to navigate from island B to island C is approximately 38.213º.
Step-by-step explanation:
The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:
(1)
Where:
- The distance from A to C, measured in miles.
- The distance from A to B, measured in miles.
- The distance from B to C, measured in miles.
- Bearing from island B to island C, measured in sexagesimal degrees.
Then, we clear the bearing angle within the equation:
(2)
If we know that 
, 
, 
, then the bearing from island B to island C:
![\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%287%5Cmi%29%5E%7B2%7D%2B%288%5C%2Cmi%29%5E%7B2%7D-%285%5C%2Cmi%29%5E%7B2%7D%7D%7B2%5Ccdot%20%288%5C%2Cmi%29%5Ccdot%20%287%5C%2Cmi%29%7D%20%5Cright%5D)
The bearing needed to navigate from island B to island C is approximately 38.213º.
