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BartSMP [9]
3 years ago
10

Find X pleaseee :).

Mathematics
1 answer:
larisa [96]3 years ago
5 0

Answer:

22

Step-by-step explanation:

(5x-7 )+(4x-11)=180 ( it equals 180 because those two angles equal 180)

Then add the similar things together

5x+4x=9x

-7-11= -18

9x-18=180, add 18 on both sides to get 9x alone

9x=180, then divide 180 by 9 to get x alone

x=22

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Numbers like 10,100,1000, and so on are called blank
Evgen [1.6K]
Multiples of 10.

Is that what you are asking?
6 0
3 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

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5 0
2 years ago
What's the answer and how to get it
Murrr4er [49]
The answer is B.)
The answers are using the distributive property. The distributive property multiplies both the numbers inside the parenthesis by the number that's on the outside of the parenthesis.
6x3 = 18, 6x4x=24x.
Hope this helps :) work hard!
8 0
3 years ago
How do the absolute values of -8 1/2 and -9 1/2 compare? Choose a symbol
Cloud [144]

Answer: its <

Step-by-step explanation:

4 0
3 years ago
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stiks02 [169]

Answer:

Option a) h=\frac{3V}{\pi r^{2} }

Step-by-step explanation:

The given formula seems to represent the volume of right circular cone. The correct formula is:

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We have to rearrange the formula for h. This means we have to move h on one side of the formula and all the other variables and constants on the other side of the equation. This can be done as shown below:

V=\frac{1}{3} \pi r^{2} h\\\\3V=\pi r^{2} h\\\\h=\frac{3V}{\pi r^{2} }

5 0
3 years ago
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