stadium has 49,000 seats. Seats sell for $42 in Section A, $36 in Section B, and $30 in Section C. The number of seats in S
ection A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,849,800 from each sold-out event. How many seats does each section hold?
From here, simplify the equation by dividing each term by the greatest common factor: 6.
36B + 30C = 822600 becomes 6B + 5C = 137100
Now you have stackable simultaneous equations that you can easily work with:
6B + 5C = 137100
B + C = 24500
Multiply the terms in the second equation by either 6 or 5 so that you can subtract the second equation from the first equation and cancel out the B or C, respectively.
Example:
6B + 5C = 137100
minus 5B + 5C = 122500
equals B = 14600
Then plug your answer into the B + C = 24500 equation to find C.
Finally plug B and C into the A + C + B = 49000 equation to get A.
