Answer:
Solution: C) 7.815
Hint: From Chi-square table with (k-r-1)=(6-2-1) = 3 d.f the critical value = 7.8147
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Decided by 12 is 2 your welcome
Answer:
Step-by-step explanation:
So first you add them together which gives you infinity and then you divide infinity by (139+285) then keep doing it until you realise this is a scam
Answer:
19 1-point shots and 32 2-point shots
Step-by-step explanation:
Let x be the amount of 1-point shots they made and y be the amount of 2-point shots they made then...
x+y=51
x+2y=83
We can solve this equation using elimination. In this case, we can eliminate x be subtracting the two equations.
-y=-32
Divide both sides by -1
y=32
Plug this back into the equation to solve for x
x+32=51
Subtract 32 from both sides
x=19
They scored 19 1-point shots and 32 2-point shots.
