2 years ago

A

1 answer:

5 0

So what’s your question

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lorasvet [3.4K]

Answer:

Answer is $\frac{4}{3}$

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

$-x^2+2x=y,y=0$

$-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2$

$\int\limits^2_0 {-x^2+2x} \, dx$

Integrate.

$\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3$

Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

Proof Check your interval of x.

7 0

1 year ago

Vera_Pavlovna [14]

Simplified answer would be 60k^2+k

and you get that answer by combining like terms, Good Luck!

8 0

2 years ago

vodka [1.7K]

20 Square units jit. now give me brainliest.

3 0

2 years ago

lianna [129]

Adds 4 each time and 5-4=1 so nth term is 4n + 1

5 0

2 years ago

Anna11 [10]

1 becuse you put the deniminatoe 1

8 0

3 years ago